Verified Solution • 2025–26 Session moderate

QJEEM22Chd29d: JEE Main 2022 Chemistry - Class 12 JEEM22Chd29d Solution: Boiling point of a 2 % aqueous solution of a non-volatile…

Boiling point of a 2% aqueous solution of a non-volatile solute A is equal to the boiling point of 8% aqueous solution of a non-volatile solute B. The relation between molecular weights of A and B is

Multiple Choice Options

  • A MA=4MB
  • B MB=4MA
  • C MA=8MB
  • D MB=8MA

Step-by-Step Verified Solution

For A:100 gm\mathbf{A}: 100 \,\mathrm{gm} solution →2 gm\rightarrow 2 \,\mathrm{gm} solute A\mathrm{A}

∴\therefore Molality =2/MA0.098=\frac{2 / \mathrm{M}_{\mathrm{A}}}{0.098}

For B : 100 gm100 \,\mathrm{gm} solution →8 gm\rightarrow 8 \,\mathrm{gm} solute B\mathrm{B}

∴ Molality =8/MB0.092∵(ΔTB)A=(ΔTB)B

∴\therefore Molality of A=\mathrm{A}= Molality of B\mathrm{B}

∴20.098MA=80.092MB

298×928=MAMB

14.261=MAMB

∴MB=4.261×MA

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