Verified Solution • 2025–26 Session moderate

QJEEM22Chc449: JEE Main 2022 Chemistry - Class 12 JEEM22Chc449 Solution: The resistance of a conductivity cell containing 0.01 M KCl…

The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω. If the conductivity of 0.01 M KCl solution at 298 K is 0.152 × 10−3 S cm−1, then the cell constant of the conductivity cell is ____________ × 10−3 cm−1.

Step-by-Step Verified Solution

Molarity of KCl\mathrm{KCl} solution =0.1 M=0.1 ~\mathrm{M}

 Resistance =1750 ohm Conductivity =0.152×10−3 S cm−1 Conductivity = Cell constant  Resistance ∴ Cell constant =0.152×10−3×1750=266×10−3 cm−1

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