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QJEEM22Chc418: JEE Main 2022 Chemistry - Class 12 JEEM22Chc418 Solution: Metal deficiency defect is shown by Fe 0.93 O. In the crystal,…

Metal deficiency defect is shown by Fe0.93O. In the crystal, some Fe2+ cations are missing and loss of positive charge is compensated by the presence of Fe3+ ions. The percentage of Fe2+ ions in the Fe0.93O crystals is __________. (Nearest integer)

Step-by-Step Verified Solution

Fe0.93O\mathrm{Fe}_{0.93} \mathrm{O}

Let the number of O−2\mathrm{O}^{-2} ions be 100 and the number of Fe+2\mathrm{Fe}^{+2} ions be X\mathrm{X} The number of Fe+3\mathrm{Fe}^{+3} ions be (93−X)(93-\mathrm{X})

amp;∴ X(2)+(93−X)3=200amp;279−X=200amp;X=79amp;∴% of F+2 ions =7993×100amp;≃85%\begin{aligned}&\therefore \,X(2)+(93-X) 3=200 \\\\&279-X=200 \\\\&X=79 \\\\&\therefore \quad \% \text { of } F^{+2} \text { ions } =\frac{79}{93} \times 100 \\\\&\simeq 85 \%\end{aligned}

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