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QJEEM22Chc1b0: JEE Main 2022 Chemistry - Class 12 JEEM22Chc1b0 Solution: of acetic acid was contaminated with ascorbic acid to lower…

150 g150 \mathrm{~g} of acetic acid was contaminated with 10.2 g10.2 \mathrm{~g} ascorbic acid (C6H8O6)\left(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}\right) to lower down its freezing point by (x×10−1)∘C\left(x \times 10^{-1}\right)^{\circ} \mathrm{C} . The value of xx is ___________. (Nearest integer)

[Given Kf=3.9 K kg mol−1\mathrm{K}_{f}=3.9 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1} ; molar mass of ascorbic acid =176 g mol−1=176 \mathrm{~g} \mathrm{~mol}^{-1} ]

Step-by-Step Verified Solution

M.wt. of Acetic acid =60 g=60 \mathrm{~g}

M.wt. of Ascorbic acid =176 g=176 \mathrm{~g}

ΔTf=Kfm\Delta T_{f}=K_{f} m

ΔTfamp;=3.9×10.2×1000176×150ΔTfamp;=1.506amp;=15.06×10−1amp;=15\begin{aligned}\Delta T_{f} &=\frac{3.9 \times 10.2 \times 1000}{176 \times 150} \\\\\Delta T_{f} &=1.506 \\\\&=15.06 \times 10^{-1} \\\\&=15\end{aligned}

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