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QJEEM22Chc0d4: JEE Main 2022 Chemistry - Class 12 JEEM22Chc0d4 Solution: For the decomposition of azomethane. CH 3 N 2 CH 3 (g) CH 3 CH…

For the decomposition of azomethane.

CH3N2CH3(g) →\to CH3CH3(g) + N2(g), a first order reaction, the variation in partial pressure with time at 600 K is given as

JEE Main 2022 (Online) 25th July Evening Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 66 English

The half life of the reaction is __________ ×\times 10 −- 5 s. [Nearest integer]

Step-by-Step Verified Solution

For first order reaction,

amp;ln⁡A=ln⁡A0−ktamp; Hence Slope =−kamp;−k=−3.465×104amp;k=0.693t1/2amp;3.465×104=0.693t1/2amp;t1/2=2×10−5 s\begin{aligned}&\ln A=\ln A_{0}-k t \\&\text { Hence Slope }=-k \\&-k=-3.465 \times 10^{4} \\&k=\frac{0.693}{t_{1 / 2}} \\&3.465 \times 10^{4}=\frac{0.693}{t_{1 / 2}} \\&t_{1 / 2}=2 \times 10^{-5} \mathrm{~s}\end{aligned}

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