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QJEEM22Chbff0: JEE Main 2022 Chemistry - Class 11 JEEM22Chbff0 Solution: The standard entropy change for the reaction 4Fe(s) + 3O 2 (g)…

The standard entropy change for the reaction

4Fe(s) + 3O2(g) → 2Fe2O3(s) is −550 J K−1 at 298 K.

[Given : The standard enthalpy change for the reaction is −165 kJ mol−1]. The temperature in K at which the reaction attains equilibrium is _____________. (Nearest Integer)

Step-by-Step Verified Solution

ΔG=ΔH−TΔS=0\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}=0 at equilibrium

⇒−165×103−T×(−505)=0⇒T=300 K

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