QJEEM22Chbc04: JEE Main 2022 Chemistry - Class 12 JEEM22Chbc04 Solution: For a first order reaction, the time required for completion of …

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For a first order reaction, the time required for completion of 90% reaction is 'x' times the half life of the reaction. The value of 'x' is

(Given : ln 10 = 2.303 and log 2 = 0.3010)

Accepted Answer

A \to

Products

For a first order reaction,

t_{1 / 2} = \frac{\ln 2}{k} = \frac{0.693}{k}

Time for

90 %

conversion,

t_{90 %} = \frac{1}{k} \ln \frac{100}{10} = \frac{\ln 10}{k} = \frac{2.303}{k}

t_{90 %} = \frac{2.303}{0.693} t_{1 / 2} = 3.32 t_{1 / 2}

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