Verified Solution • 2025–26 Session moderate

QJEEM22Chada0: JEE Main 2022 Chemistry - Class 11 JEEM22Chada0 Solution: 2.2 g of nitrous oxide (N 2 O) gas is cooled at a constant…

2.2 g of nitrous oxide (N2O) gas is cooled at a constant pressure of 1 atm from 310 K to 270 K causing the compression of the gas from 217.1 mL to 167.75 mL. The change in internal energy of the process, Δ\Delta U is ' −- x' J. The value of 'x' is ________. [nearest integer]

(Given : atomic mass of N = 14 g mol −- 1 and of O = 16 g mol −- 1. Molar heat capacity of N2O is 100 J K −- 1 mol −- 1)

Step-by-Step Verified Solution

ΔT=−40 K\Delta T=-40 \mathrm{~K}

ΔUamp;=q+wamp;=100×2.244(−40)−(−49.39)×10−3×101.325\begin{aligned}\Delta U &=q+w \\\\&=\frac{100 \times 2.2}{44}(-40)-(-49.39) \times 10^{-3} \times 101.325\end{aligned}

amp;=−200+5amp;=−195 Jx=amp;195\begin{aligned}&=-200+5 \\\\&=-195 \mathrm{~J} \\\\\mathrm{x}=& 195\end{aligned}

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