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QJEEM22Chaa48: JEE Main 2022 Chemistry - Class 12 JEEM22Chaa48 Solution: [ Fe ( CN ) 6 ] 3 − should be an inner orbital complex.…

[Fe(CN)6]3− should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is (−) ____________ Δ0. (Nearest integer)

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In [Fe(CN)6]3−\left[\mathrm{Fe}(\mathrm{CN})^{6}\right]^{3-} , Fe\mathrm{Fe} is present in (+3) oxidation state Fe(III)⇒\mathrm{Fe}(\mathrm{III}) \Rightarrow inner orbital complex ⇒d5\Rightarrow d^{5} (with pairing)

Configuration ⇒t2g5\Rightarrow t_{2 g}^{5}

CFSE =5×−25Δ0=−2Δ0=5 \times \frac{-2}{5} \Delta_{0}=-2 \Delta_{0}

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