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QJEEM22Cha8eb: JEE Main 2022 Chemistry - Class 11 JEEM22Cha8eb Solution: Blister copper is produced by reaction of copper oxide with…

Blister copper is produced by reaction of copper oxide with copper sulphide.

2Cu2O + Cu2S →\to 6Cu + SO2

When 2.86 ×\times 103 g of Cu2O and 4.77 ×\times 103 g of Cu2S are used for reaction, the mass of copper produced is _____________ g. (nearest integer)

(Atomic mass of Cu = 63.5 a.m. u, S = 32.0 a.m. u, O = 16.0 a.m. u)

Step-by-Step Verified Solution

moles of Cu2O=2.86×103143=20\mathrm{Cu}_{2} \mathrm{O}=\frac{2.86 \times 10^{3}}{143}=20

moles of Cu2S=4.77×103159=30\mathrm{Cu}_{2} \mathrm{S}=\frac{4.77 \times 10^{3}}{159}=30

Cu2O\mathrm{Cu}_{2} \mathrm{O} is limiting reagent

2Cu2Oamp;+amp;Cu2 S⟶amp;6Cuamp;+amp;SO220amp;amp;30amp;−amp;amp;−−amp;amp;20amp;60amp;amp;10\begin{array}{lccc}2 \mathrm{Cu}_{2} \mathrm{O} & + & \mathrm{Cu}_{2} \mathrm{~S} \longrightarrow & 6 \mathrm{Cu} & + & \mathrm{SO}_{2} \\20 && 30 & - & & - \\- & &20 & 60 & & 10\end{array}

Mass of copper =60×63.5=3810 g=60 \times 63.5=3810 \mathrm{~g}

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