Verified Solution • 2025–26 Session moderate

QJEEM22Cha645: JEE Main 2022 Chemistry - Class 12 JEEM22Cha645 Solution: The osmotic pressure of blood is 7.47 bar at 300 K. To inject…

The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL−1 is _____________.

(Molar mass of glucose = 180 g mol−1, R = 0.083 L bar K−1 mol−1) (Nearest integer)

Step-by-Step Verified Solution

7.47=C×0.083×3007.47=\mathrm{C} \times 0.083 \times 300

(π=CRT)(\pi=\mathrm{CRT})

(Where C represents the concentration of glucose solution and π\pi represents osmotic pressure)

C=7.470.083×300( mol L−1)\mathrm{C}=\frac{7.47}{0.083 \times 300}\left(\mathrm{~mol} \mathrm{~L}^{-1}\right)

which in gm/L=7.470.083×300×180\mathrm{gm} / \mathrm{L}=\frac{7.47}{0.083 \times 300} \times 180

=54gm/l

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