Verified Solution • 2025–26 Session moderate

QJEEM22Cha47d: JEE Main 2022 Chemistry - Class 11 JEEM22Cha47d Solution: The correct order of density is :

The correct order of density is :

Multiple Choice Options

  • A Be > Mg > Ca > Sr
  • B Sr > Ca > Mg > Be
  • C Sr > Be > Mg > Ca
  • D Be > Sr > Mg > Ca

Step-by-Step Verified Solution

Density of Sr=2.63 g/cm3\mathrm{Sr}=2.63 \mathrm{~g} / \mathrm{cm}^{3}

Density of Be=1.84 g/cm3\mathrm{Be}=1.84 \mathrm{~g} / \mathrm{cm}^{3}

Density of Mg=1.74 g/cm3\mathrm{Mg}=1.74 \mathrm{~g} / \mathrm{cm}^{3}

Density of Ca=1.55 g/cm3\mathrm{Ca}=1.55 \mathrm{~g} / \mathrm{cm}^{3}

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