QJEEM22Ch9f4d: JEE Main 2022 Chemistry - Class 12 JEEM22Ch9f4d Solution: For the given reactions Sn 2+ + 2e − → Sn Sn 4+ + 4e − → Sn the …

For the given reactions

Sn²⁺ + 2e^$$-$$ $$\to$$ Sn

Sn⁴⁺ + 4e^$$-$$ $$\to$$ Sn

the electrode potentials are ; $$E_{S{n}^{2+}/Sn}^o=-0.140$$ V and $$E_{S{n}^{4+}/Sn}^o=+0.010$$ V. The magnitude of standard electrode potential for $$S{n}^{4+}/S{n}^{2+}$$ i.e. $$E_{S{n}^{4+}/S{n}^{2+}}^o$$ is _____________ $$\times$$ 10^$$-$$2 V. (Nearest integer)