Verified Solution • 2025–26 Session moderate

QJEEM22Ch9ce4: JEE Main 2022 Chemistry - Class 11 JEEM22Ch9ce4 Solution: on reaction with excess of water results into acidic mixture 16 …

SO2Cl2\mathrm{SO}_{2} \mathrm{Cl}_{2} on reaction with excess of water results into acidic mixture

SO2Cl2+2H2O→H2SO4+2HCl\mathrm{SO}_{2} \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+2 \mathrm{HCl}

16 moles of NaOH\mathrm{NaOH} is required for the complete neutralisation of the resultant acidic mixture. The number of moles of SO2Cl2\mathrm{SO}_{2} \mathrm{Cl}_{2} used is :

Multiple Choice Options

  • A 4
  • B 2
  • C 16
  • D 8

Step-by-Step Verified Solution

SO2Cl2+2H2O→H2SO4+2HCl\mathrm{SO}_{2} \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+2 \mathrm{HCl}

Moles of NaOH\mathrm{NaOH} required for complete neutralization of resultant acidic mixture =16=16 moles

And 1 mole of SO2Cl2\mathrm{SO}_{2} \mathrm{Cl}_{2} produced 4 moles of H+\mathrm{H}^{+} .

∴\therefore Moles of SO2Cl2\mathrm{SO}_{2} \mathrm{Cl}_{2} used will be =164=4=\frac{16}{4}=4 moles

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