Verified Solution • 2025–26 Session moderate

QJEEM22Ch9097: JEE Main 2022 Chemistry - Class 12 JEEM22Ch9097 Solution: The vapour pressures of two volatile liquids A and B at 25 C…

The vapour pressures of two volatile liquids A and B at 25 ∘^\circ C are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0.3 mole fraction of A, then the mole fraction of liquid B in the vapour phase is x17{x \over {17}} . The value of x is ______________.

Step-by-Step Verified Solution

amp;yB1−yB=PBoPAo[XB1−XB]amp;⇒yB1−yB=10050[0.70.3]=143amp;⇒yB=1417\begin{aligned}&\frac{\mathrm{y}_{\mathrm{B}}}{1-\mathrm{y}_{\mathrm{B}}}=\frac{\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}\left[\frac{\mathrm{X}_{\mathrm{B}}}{1-\mathrm{X}_{\mathrm{B}}}\right] \\\\&\Rightarrow \frac{\mathrm{y}_{\mathrm{B}}}{1-\mathrm{y}_{\mathrm{B}}}=\frac{100}{50}\left[\frac{0.7}{0.3}\right]=\frac{14}{3} \\\\&\Rightarrow \mathrm{y}_{\mathrm{B}}=\frac{14}{17}\end{aligned}

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