Verified Solution • 2025–26 Session moderate

QJEEM22Ch8ed3: JEE Main 2022 Chemistry - Class 11 JEEM22Ch8ed3 Solution: The products obtained during treatment of hard water using…

The products obtained during treatment of hard water using Clark's method are :

Multiple Choice Options

  • A CaCO3\mathrm{CaCO}_{3} and MgCO3\mathrm{MgCO}_{3}
  • B Ca(OH)2\mathrm{Ca}(\mathrm{OH})_{2} and Mg(OH)2\mathrm{Mg}(\mathrm{OH})_{2}
  • C CaCO3\mathrm{CaCO}_{3} and Mg(OH)2\mathrm{Mg}(\mathrm{OH})_{2}
  • D Ca(OH)2\mathrm{Ca}(\mathrm{OH})_{2} and MgCO3\mathrm{MgCO}_{3}

Step-by-Step Verified Solution

In Clark's method lime water is used

amp;Ca(HCO3)2+2Ca(OH)2→2CaCO3+2H2Oamp;Mg(HCO3)2+2Ca(OH)2→2CaCO3+Mg(OH)2+2H2O\begin{aligned}&\mathrm{Ca}\left(\mathrm{HCO}_3\right)_2+2 \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 2 \mathrm{CaCO}_3+2 \mathrm{H}_2 \mathrm{O} \\\\&\mathrm{Mg}\left(\mathrm{HCO}_3\right)_2+2 \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 2 \mathrm{CaCO}_3+\mathrm{Mg}(\mathrm{OH})_2+2 \mathrm{H}_2 \mathrm{O}\end{aligned}

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