QJEEM22Ch8c43: JEE Main 2022 Chemistry - Class 12 JEEM22Ch8c43 Solution: C 6 H 12 O 6 ⟶ Zymase A B + CHI 3 The number of carbon atoms…

Question

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C₆H₁₂O₆ $\overset{Zymase}{⟶}$ A $\mathrel{\mathop{\kern0pt\longrightarrow}\limits_\Delta ^\text{NaOI}}$ B + CHI₃

The number of carbon atoms present in the product B is _______________.

Accepted Answer

\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6 \stackrel{\text { Zymase }}{\longrightarrow} \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \stackrel{\mathrm{NaOl}}{\longrightarrow} \underset{\text { (B) }}{\mathrm{HCOONa}}+\mathrm{CHI}_3

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