QJEEM22Ch8145: JEE Main 2022 Chemistry - Class 11 JEEM22Ch8145 Solution: Match List - I with List - II. .tg…

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Match List - I with List - II.

	List - I		List - II
(A)	$ψ_{MO} = ψ_{A} - ψ_{B}$	(I)	Dipole moment
(B)	$μ = Q \times r$	(II)	Bonding molecular orbital
(C)	$\frac{N_{b} - N_{a}}{2}$	(III)	Anti-bonding molecular orbital
(D)	$ψ_{MO} = ψ_{A} + ψ_{B}$	(IV)	Bond order

Choose the correct answer from the options given below :

Accepted Answer

\Psi_{A}-\Psi_{B}=\Psi_{M O}

is anti-boding molecular orbital

\begin{aligned} μ = Q \times r is dipole moment \\ \frac{N_{b} - N_{a}}{2} = bond order \\ Ψ_{A} + Ψ_{B} = Ψ_{MO} is boding molecular orbital. \end{aligned}

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