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QJEEM22Ch7de3: JEE Main 2022 Chemistry - Class 11 JEEM22Ch7de3 Solution: On complete combustion of 0.492   g of an organic compound …

On complete combustion of 0.492 g of an organic compound containing C,H and O, 0.7938 g of CO2 and 0.4428 g of H2O was produced. The % composition of oxygen in the compound is ___________.

Step-by-Step Verified Solution

%\% of H=218× wt. of H2O wt. of organic compound ×100\mathrm{H}=\frac{2}{18} \times \frac{\text { wt. of } \mathrm{H}_{2} \mathrm{O}}{\text { wt. of organic compound }} \times 100

=218×0.44280.492×100=0.11×0.9×100=0.099×100=9.9

%\% of C=1244×0.79380.492×100C=\frac{12}{44} \times \frac{0.7938}{0.492} \times 100

=0.27×1.61×100=43.47

% Oxygen =100−(43.47+9.9)

=100−53.37≃46=100-53.37 \simeq 46

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