QJEEM22Ch7823: JEE Main 2022 Chemistry - Class 11 JEEM22Ch7823 Solution: Consider the above reaction, the limiting reagent of the…

Question

Verified Solution • 2025–26 Session moderate

$\mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{NH}_{3(\mathrm{~g})}$

$20 \mathrm{~g} \quad ~~~5 \mathrm{~g}$

Consider the above reaction, the limiting reagent of the reaction and number of moles of $\mathrm{NH}_{3}$ formed respectively are :

Accepted Answer

\underset{20 \,g}{\mathrm{N}_{2(\mathrm{~g})}}+\underset{5 \mathrm{~g}}{3 H_{2(g)}} \rightleftharpoons 2 \mathrm{NH}_{3(\mathrm{~g})}

Ideally

28 \mathrm{~g} \mathrm{~N}_{2}

reacts with

6 \mathrm{~g} \,\mathrm{H}_{2}

limiting reagent is

\mathrm{N}_{2}

\therefore

Amount of

\mathrm{NH}_{3}

formed on reacting

20 \mathrm{~g} \mathrm{~N}_2

is,

\begin{aligned}&amp;=\frac{34 \times 20}{28}=24.28 \mathrm{~g} \\\\&amp;=1.42 \text { moles }\end{aligned}

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