Verified Solution • 2025–26 Session moderate

QJEEM22Ch7358: JEE Main 2022 Chemistry - Class 11 JEEM22Ch7358 Solution: The normality of H 2 SO 4 in the solution obtained on mixing…

The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1MH2SO4 with 50 mL of 0.1MNaOH is _______________ ×10−1 N. (Nearest Integer)

Step-by-Step Verified Solution

No. of equivalents of H2SO4=100×0.1×2=20\mathrm{H}_2 \mathrm{SO}_4=100 \times 0.1 \times 2=20

No. of equivalents of NaOH=50×0.1=5\mathrm{NaOH}=50 \times 0.1=5

No. of equivalents of H2SO4\mathrm{H}_2 \mathrm{SO}_4 left =20−5=15=20-5=15

⇒150×x=15x=110=0.1 N=1×10−1 N

Related Learning Resources & Exam Preparation