Verified Solution • 2025–26 Session moderate

QJEEM22Ch70c9: JEE Main 2022 Chemistry - Class 11 JEEM22Ch70c9 Solution: 0.2 g of an organic compound was subjected to estimation of…

0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of N2 evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is _________. [nearest integer]

(Given : Molar mass of N2 is 28 g mol −- 1. Molar volume of N2 at STP : 22.4 L)

Step-by-Step Verified Solution

Given volume of N2 = 22.400 mL

∴\therefore Moles of N2 = 22.40022400=10−3{{22.400} \over {22400}} = {10^{ - 3}} mole

∴\therefore Moles of N atoms = 2 ×\times 10 −- 3 mole

∴\therefore Weigh of N atoms = 14 ×\times 2 ×\times 10 −- 3 mole

= 28 ×\times 10 −- 3 mole

∴\therefore % of N atom in the compound

=28×10−30.2×100= {{28 \times {{10}^{ - 3}}} \over {0.2}} \times 100

= 14

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