QJEEM22Ch6c7a: JEE Main 2022 Chemistry - Class 11 JEEM22Ch6c7a Solution: A commercially sold conc. HCl is 35% HCl by mass. If the…

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A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is:

(Atomic mass : Cl = 35.5 amu, H = 1 amu)

Accepted Answer

35% HCl by mass means in 100 gm HCl solution 35 gm HCl present.

Now, volume of 100 gm HCl solution

$= \frac{100}{1.46}$ ml

$= \frac{\frac{100}{1.46}}{1000}$ l

Moles of HCl $= \frac{35}{36.5}$

Now, molarity $= \frac{m o l e s o f s o l u t e}{v o l u m e o f s o l u t i o n (i n L)}$

$= \frac{\frac{35}{36.5}}{\frac{\frac{100}{1.46}}{1000}} = 14$

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