QJEEM22Ch6690: JEE Main 2022 Chemistry - Class 12 JEEM22Ch6690 Solution: The above reaction has been studied at . The related data are…

Question

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$2 \mathrm{NO}+2 \mathrm{H}_{2} \rightarrow \mathrm{N}_{2}+2 \mathrm{H}_{2} \mathrm{O}$

The above reaction has been studied at $800^{\circ} \mathrm{C}$ . The related data are given in the table below

Reaction serial number	Initial Pressure of ${H_2}/kPa$	Initial Pressure of $NO/kPa$	Initial rate $\left( {{{ - dp} \over {dt}}} \right)/(kPa/s)$
1	65.6	40.0	0.135
2	65.6	20.1	0.033
3	38.6	65.6	0.214
4	19.2	65.6	0.106

The order of the reaction with respect to NO is ___________.

Accepted Answer

Let the rate of reaction (

r

) is as

\mathrm{r}=\mathrm{K}[\mathrm{NO}]^{n}\left[\mathrm{H}_{2}\right]^{\mathrm{m}}

From

1^{\text {st }}

data

0.135=\mathrm{K}[40]^{\mathrm{n}} \cdot(65.6)^{\mathrm{m}}\quad\quad...(1)

From

2^{\text {nd }}

data

0.033=\mathrm{K}(20.1)^{\mathrm{n}} \cdot(65.6)^{\mathrm{m}}\quad\quad...(2)

On dividing equation (1) by equation (2)

\begin{aligned}&amp;\frac{0.135}{0.033}=\left(\frac{40}{20.1}\right)^{n} \\\\&amp;4=(2)^{n} \\\\&amp;\therefore n=2 \\\\&amp;\therefore \text { Order of reaction w.r.t. NO is } 2 .\end{aligned}

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