QJEEM22Ch615d: JEE Main 2022 Chemistry - Class 11 JEEM22Ch615d Solution: On complete combustion 0.30 g of an organic compound gave 0.20…

${C_x}{H_y} + \left( {x + {y \over 4}} \right){O_2} \to x\,C{O_2} + {y \over 2}{H_2}O$

Given organic compound C_xH_y= 0.3 gm

Produced carbon dioxide (CO₂) = 0.2 gm

Produced water (H₂O) = 0.1 gm

Moles of CO₂ = ${{0.2} \over {44}}$

$\therefore$ Moles of C atom = ${{0.2} \over {44}}$

$\therefore$ Mass of C atom = ${{0.2} \over {44}}$ $\times$ 12 = 0.0545

Moles of H₂O = ${{0.1} \over {18}}$

$\therefore$ Moles of H atoms = ${{0.1} \over {18}}$ $\times$ 2

$\therefore$ Mass of H atoms = ${{0.1} \times2\over {18}}$ $\times$ 1 = 0.0111

$\therefore$ % of C atom = ${{0.0545} \over {0.3}}$ $\times$ 100 = 18%