Verified Solution • 2025–26 Session moderate

QJEEM22Ch59c4: JEE Main 2022 Chemistry - Class 11 JEEM22Ch59c4 Solution: A sample of of an organic compound when analyzed by Duma's…

A sample of 0.125 g0.125 \mathrm{~g} of an organic compound when analyzed by Duma's method yields 22.78 mL22.78 \mathrm{~mL} of nitrogen gas collected over KOH\mathrm{KOH} solution at 280 K280 \mathrm{~K} and 759 mm Hg759 \mathrm{~mm}\, \mathrm{Hg} . The percentage of nitrogen in the given organic compound is __________. (Nearest integer)

Given :

(a) The vapour pressure of water of 280 K280 \mathrm{~K} is 14.2 mm Hg14.2 \mathrm{~mm} \,\mathrm{Hg} .

(b) R=0.082 L\mathrm{R}=0.082 \mathrm{~L} atm K−1 mol−1\mathrm{K}^{-1} \mathrm{~mol}^{-1}

Step-by-Step Verified Solution

Pactual =759−14.2=744.8 mmHgP_{\text {actual }}=759-14.2=744.8 \,\mathrm{mmHg}

nN2amp;=744.8×22.78760×0.0821×280×1000amp;=0.000971 mol\begin{aligned}\mathrm{n}_{\mathrm{N}_{2}} &=\frac{744.8 \times 22.78}{760 \times 0.0821 \times 280 \times 1000} \\\\&=0.000971 \mathrm{~mol}\end{aligned}

Mass of N2=0.02719 gm\mathrm{N}_{2}=0.02719 \,\mathrm{gm}

Percentage of nitrogen

=0.02710.125×100=21.75≃22=\frac{0.0271}{0.125} \times 100=21.75 \simeq 22

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