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QJEEM22Ch55f6: JEE Main 2022 Chemistry - Class 12 JEEM22Ch55f6 Solution: The number of terminal oxygen atoms present in the product B…

The number of terminal oxygen atoms present in the product B obtained from the following reaction is _____________.

FeCr2O4 + Na2CO3 + O2 → A + Fe2O3 + CO2

A + H+ → B + H2O + Na+

Step-by-Step Verified Solution

FeCr2O4+Na2CO3+O2⟶Fe2O3+CO2\mathrm{FeCr}_{2} \mathrm{O}_{4}+\mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{O}_{2} \longrightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}+\mathrm{CO}_{2} +Na2CrO4+\mathrm{Na}_{2} \mathrm{CrO}_{4} (A)

Na2CrO4+H+⟶Cr2O7−2+H2O+Na+

JEE Main 2022 (Online) 29th June Morning Shift Chemistry - d and f Block Elements Question 107 English Explanation

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