QJEEM22Ch55a8: JEE Main 2022 Chemistry - Class 11 JEEM22Ch55a8 Solution: The pressure of a moist gas at is . The volume of the container …
The pressure of a moist gas at is . The volume of the container is doubled at the same temperature. The new pressure of the moist gas is ________________ . (Nearest integer)
(Given : The vapour pressure of water at is )
Step-by-Step Verified Solution
To solve this problem, we need to determine the new pressure of the moist gas when the volume of the container is doubled while maintaining the same temperature. First, we need to separate the contributions of the gas and the water vapor to the initial pressure and then apply Boyle's Law for the gas component only. The steps are as follows:
1. Initial pressure of the moist gas (gas + water vapor) is given as .
The vapour pressure of water at is .
2. The partial pressure of the dry gas component can be calculated by subtracting the vapor pressure of water from the initial pressure:
3. When the volume of the container is doubled, the pressure of the dry gas component will change according to Boyle's Law, which states:
Since the temperature remains constant and the volume is doubled (i.e., ), we can find the new pressure of the dry gas ( ) with the equation:
Solving for :
4. The vapor pressure of water remains unchanged at because it depends only on the temperature, not on the volume.
5. The new total pressure of the moist gas is the sum of the new pressure of the dry gas and the unchanged vapor pressure of water:
6. Finally, as requested, we express the new pressure in the form of and find the nearest integer:
Therefore, the nearest integer is 22.