Verified Solution • 2025–26 Session moderate

QJEEM22Ch54a0: JEE Main 2022 Chemistry - Class 11 JEEM22Ch54a0 Solution: G vs T plot for the formation of MgO, involving reaction 2Mg +…

Δ\Delta G ∘^\circ vs T plot for the formation of MgO, involving reaction

2Mg + O2 →\to 2MgO, will look like :

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/9024820d4b0d10dfa9c376373da4a888b3617fd737090045a150fbf7587fd902.webp
  • B https://ik.imagekit.io/novatra/photos/a5130e1ab09ee3943b08adfc6e784391bb707b3185a71954b1e2e7a73147adf4.webp
  • C https://ik.imagekit.io/novatra/photos/9d5f35c54a8712fa1244d85fa9277868372c93d0bc6d5f9191d1e027a364a1d5.webp
  • D https://ik.imagekit.io/novatra/photos/753ef6efe073a67b193b03c1faff310dcd39c05c9dbd896887f7479d24925fca.webp

Step-by-Step Verified Solution

For the reaction,

amp;2Mg(s)+O2( g)⟶2MgO(s)amp;ΔS∘=−veamp;ΔG∘=ΔH∘−TΔS∘\begin{aligned}&2 \mathrm{Mg}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{MgO}(\mathrm{s}) \\\\&\Delta S^{\circ}=-v e \\\\&\Delta G^{\circ}=\Delta H^{\circ}-T \Delta S^{\circ}\end{aligned}

−TΔS∘-T \Delta S^{\circ} is positive,

Hence, ΔG∘\Delta G^{\circ} increase with increase in temperature.

Also, when there is phase change there is an abrupt increase in the slope.

Related Learning Resources & Exam Preparation