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QJEEM22Ch500f: JEE Main 2022 Chemistry - Class 12 JEEM22Ch500f Solution: The rate constants for decomposition of acetaldehyde have been…

The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700 - 1000 K. The data has been analysed by plotting ln k vs 103T{{{{10}^3}} \over T} graph. The value of activation energy for the reaction is ___________ kJ mol −- 1. (Nearest integer)

(Given : R = 8.31 J K −- 1 mol −- 1)

JEE Main 2022 (Online) 24th June Morning Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 69 English

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JEE Main 2022 (Online) 24th June Morning Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 69 English Explanation
ln⁡k=ln⁡A−EaRT\ln \mathrm{k}=\ln \mathrm{A}-\frac{\mathrm{E}_{\mathrm{a}}}{\mathrm{RT}}

∴\therefore Slope of the graph =−EaR×103=−18.5=-\frac{E_{a}}{R \times 10^{3}}=-18.5

∴Ea=18.5×8.31×1000≃154 kJ mol−1\therefore E_{a}=18.5 \times 8.31 \times 1000 \simeq 154 \mathrm{~kJ} \mathrm{~mol}^{-1}

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