Verified Solution • 2025–26 Session moderate

QJEEM22Ch4e28: JEE Main 2022 Chemistry - Class 11 JEEM22Ch4e28 Solution: BeCl 2 reacts with LiAlH 4 to give :

BeCl2 reacts with LiAlH4 to give :

Multiple Choice Options

  • A Be + Li[AlCl4] + H2
  • B Be + AlH3 + LiCl + HCl
  • C BeH2 + LiCl + AlCl3
  • D BeH2 + Li[AlCl4]

Step-by-Step Verified Solution

2BeCl2 + LiAlH4 → 2 BeH2 + LiCl + AlCl3

The above reaction using LiAlH4 is an important preparation method for production of hydrides.

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