Verified Solution • 2025–26 Session moderate

QJEEM22Ch48f3: JEE Main 2022 Chemistry - Class 12 JEEM22Ch48f3 Solution: 2.5 g of protein containing only glycine (C 2 H 5 NO 2 ) is…

2.5 g of protein containing only glycine (C2H5NO2) is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be 5.03 × 10−3 bar. The total number of glycine units present in the protein is ____________.

(Given : R = 0.083 L bar K−1 mol−1)

Step-by-Step Verified Solution

Since,

π=icRT

5.03×10−3=2.5M×1000500×0.083×3005.03 \times 10^{-3}=\frac{2.5}{M} \times \frac{1000}{500} \times 0.083 \times 300

Molar mass of protein =24751.5 g/mol=24751.5 \mathrm{~g} / \mathrm{mol}

Number of glycine units in protein =24751.575=\frac{24751.5}{75}

=330

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