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QJEEM22Ch4730: JEE Main 2022 Chemistry - Class 12 JEEM22Ch4730 Solution: The quantity of electricity in Faraday needed to reduce 1 mol…

The quantity of electricity in Faraday needed to reduce 1 mol of Cr2O 72−_7^{2 - } to Cr3+ is ____________.

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Cr2+6O72−⟶2Cr3+\overset{+6}{\mathrm{Cr}_2} \mathrm{O}_7^{2-} \longrightarrow 2 \mathrm{Cr}^{3+}

∵\because Each Cr\mathrm{Cr} is converting from +6+6 to +3+3

∴6\therefore 6 faradays of charge is required

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