QJEEM22Ch4569: JEE Main 2022 Chemistry - Class 11 JEEM22Ch4569 Solution: For the reaction H 2 F 2 (   g ) → H 2 (   g ) + F 2…

Question

Verified Solution • 2025–26 Session moderate

For the reaction

$H_{2} F_{2} (g) \to H_{2} (g) + F_{2} (g)$

$Δ U = - 59.6 kJ {mol}^{- 1}$ at $27^{\circ} C$ .

The enthalpy change for the above reaction is ( $-$ ) __________ $kJ {mol}^{- 1}$ [nearest integer]

Given: $R = 8.314 J K^{- 1} {mol}^{- 1}$ .

Accepted Answer

\mathrm{H}_{2} \mathrm{~F}_{2}(\mathrm{~g}) \longrightarrow \mathrm{H}_{2}(\mathrm{~g})+\mathrm{F}_{2}(\mathrm{~g})

\Delta \mathrm{U}=-59.6 \mathrm{~kJ} \mathrm{~mol}^{-1}

at

27^{\circ} \mathrm{C}

\begin{aligned} Δ H & = Δ U + Δ n_{g} RT \\ = - 59.6 + \frac{1 \times 8.314 \times 300}{1000} \\ = - 57.10 kJ {mol}^{- 1} \end{aligned}

QJEEM22Ch4569: JEE Main 2022 Chemistry - Class 11 JEEM22Ch4569 Solution: For the reaction H 2 F 2 ( &nbsp; g ) → H 2 ( &nbsp; g ) + F 2…