Verified Solution • 2025–26 Session moderate

QJEEM22Ch4542: JEE Main 2022 Chemistry - Class 12 JEEM22Ch4542 Solution: (a) CoCl 3 .4NH 3 ,    (b) CoCl 3 .5NH 3 ,…

(a) CoCl3.4NH3,    (b) CoCl3.5NH3,      (c) CoCl3.6NH3    and    (d) CoCl(NO3)2.5NH3.

Number of complex(es) which will exist in cis-trans form is/are _______________.

Step-by-Step Verified Solution

CoCl3⋅4NH3⇒[Co(NH3)4Cl2]Cl\mathrm{CoCl}_{3} \cdot 4 \mathrm{NH}_{3} \Rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl}

CoCl3⋅5NH3⇒[Co(NH3)5Cl]Cl2\mathrm{CoCl}_{3} \cdot 5 \mathrm{NH}_{3} \Rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}

CoCl3⋅6NH3⇒[Co(NH3)6]Cl3\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3} \Rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}

Only [Co(NH3)4Cl2]\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] can show geometrical isomerism. Hence can exist in cis-trans form.

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