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QJEEM22Ch4447: JEE Main 2022 Chemistry - Class 12 JEEM22Ch4447 Solution: The elevation in boiling point for 1 molal solution of…

The elevation in boiling point for 1 molal solution of non-volatile solute A is 3 K. The depression in freezing point for 2 molal solution of A in the same solvent is 6 K. The ratio of Kb and Kf i.e., Kb/Kf is 1:X. The value of X is [nearest integer]

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Molality of a solution of non volatile solute (A)=1(A)=1

Elevation in boiling point is given by

ΔTb=Kbm\Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \mathrm{m}

3=Kb×1       ... (1)

Molality of (A)(A) in the same solvent =2=2

Depression in freezing point is given by

ΔTf=Kfm6=Kf×2...(2) Dividing (1) by (2) KbKf=1X=11∴X=1

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