Verified Solution • 2025–26 Session moderate

QJEEM22Ch439d: JEE Main 2022 Chemistry - Class 11 JEEM22Ch439d Solution: Consider an imaginary ion . The nucleus contains ' '% more…

Consider an imaginary ion 2248X3−{ }_{22}^{48} \mathrm{X}^{3-} . The nucleus contains ' aa '% more neutrons than the number of electrons in the ion. The value of 'a' is _______________. [nearest integer]

Step-by-Step Verified Solution

Number of electrons in 2248X3−{ }_{22}^{48} X^{3-} is 25 .

Number of neutrons =48−22=26=48-22=26 .

%\% increase in the number of neutrons over electrons

=(26−2525)100=4%=\left(\frac{26-25}{25}\right) 100=4 \%

∴a=4\therefore a=4

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