QJEEM22Ch40ef: JEE Main 2022 Chemistry - Class 11 JEEM22Ch40ef Solution: 100 g of an ideal gas is kept in a cylinder of 416 L volume at…

Given, Mass of ideal gas = 100 gm

Let the molar mass of ideal gas = M

$$\therefore$$ Number of moles of gas (n) = $$\frac{100}{M}$$

Volume of cylinder (V) = 416 L

Temperature (T) = (27 + 273)K = 300 K

Pressure (P) = 1.5 bar

R = 0.083 L bar K^$$-$$1 mol^$$-$$1

Using ideal gas equation,

PV = nRT

$$\Rightarrow 1.5\times 416=\frac{100}{M}\times 0.083\times 300$$

$$\Rightarrow$$ M = 4