Verified Solution • 2025–26 Session moderate

QJEEM22Ch3de6: JEE Main 2022 Chemistry - Class 12 JEEM22Ch3de6 Solution: The cell potential for the following cell Pt

The cell potential for the following cell

Pt |H2(g)|H+ (aq)|| Cu2+ (0.01 M)|Cu(s)

is 0.576 V at 298 K. The pH of the solution is __________. (Nearest integer)

(Given : ECu2+/Cuo=0.34E_{C{u^{2 + }}/Cu}^o = 0.34 V and 2.303 RTF=0.06{{2.303\,RT} \over F} = 0.06 V)

Step-by-Step Verified Solution

Ecell =Ecell 0−0.062log⁡[H⊕]2[Cu+2]E_{\text {cell }}=E_{\text {cell }}^{0}-\frac{0.06}{2} \log \frac{\left[\mathrm{H}^{\oplus}\right]^{2}}{\left[\mathrm{Cu}^{+2}\right]}

0.576=0.34−0.03log⁡[H⊕]2[0.01]0.576=0.34-0.03 \log \frac{\left[\mathrm{H}^{\oplus}\right]^{2}}{[0.01]}

0.576−0.34=−0.03log⁡[H⊕]2+0.03log⁡(0.01)0.576-0.34=-0.03 \log \left[\mathrm{H}^{\oplus}\right]^{2}+0.03 \log (0.01)

=0.06 pH−0.06=0.06 \,\mathrm{pH}-0.06

pH≃4.93≃5\mathrm{pH} \simeq 4.93 \simeq 5

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