Verified Solution • 2025–26 Session moderate

QJEEM22Ch3b09: JEE Main 2022 Chemistry - Class 11 JEEM22Ch3b09 Solution: pH value of 0.001 M NaOH solution is ____________.

pH value of 0.001 M NaOH solution is ____________.

Step-by-Step Verified Solution

amp;[OH−]=0.001=10−3Mamp;[H+][OH−]=10−14amp;[H+]=10−11amp;pHamp;=−log⁡[H+]=amp;−log⁡(10−11)pHamp;=11\begin{aligned}&{\left[\mathrm{OH}^{-}\right]=0.001=10^{-3} \mathrm{M}} \\\\&{\left[\mathrm{H}^{+}\right]\left[\mathrm{OH}^{-}\right]=10^{-14}} \\\\&\quad\left[\mathrm{H}^{+}\right]=10^{-11} \\\\&\begin{aligned}\mathrm{pH} &=-\log \left[\mathrm{H}^{+}\right] \\\\=&-\log \left(10^{-11}\right) \\\\\mathrm{pH} &=11\end{aligned}\end{aligned}

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