Verified Solution • 2025–26 Session moderate QJEEM22Ch3a84: JEE Main 2022 Chemistry - Class 11 JEEM22Ch3a84 Solution: For a reaction at equilibrium A(g) B(g) + C(g) the relation… For a reaction at equilibrium A(g) ⇌\rightleftharpoons⇌ B(g) + 12{1 \over 2}21 C(g) the relation between dissociation constant (K), degree of dissociation ( α\alphaα ) and equilibrium pressure (p) is given by : Multiple Choice Options A K=α12p32(1+32α)12(1−α)K = {{{\alpha ^{{1 \over 2}}}{p^{{3 \over 2}}}} \over {{{\left( {1 + {3 \over 2}\alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}K=(1+23α)21(1−α)α21p23 B K=α32p12(2+α)12(1−α)K = {{{\alpha ^{{3 \over 2}}}{p^{{1 \over 2}}}} \over {{{\left( {2 + \alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}K=(2+α)21(1−α)α23p21 C K=(α p)32(1+32α)12(1−α)K = {{{{(\alpha \,p)}^{{3 \over 2}}}} \over {{{\left( {1 + {3 \over 2}\alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}K=(1+23α)21(1−α)(αp)23 D K=(α p)32(1+α)(1−α)12K = {{{{(\alpha \,p)}^{{3 \over 2}}}} \over {{{\left( {1 + \alpha } \right)}}{{(1 - \alpha )}^{{1 \over 2}}}}}K=(1+α)(1−α)21(αp)23 Step-by-Step Verified Solution Now, KP{K_P}KP or K=PB×(PC)12PAK = {{{P_B} \times {{\left( {{P_C}} \right)}^{{1 \over 2}}}} \over {{P_A}}}K=PAPB×(PC)21 =(α1+α2)P×[(α21+α2)P]12(1−α1+α2)P= {{\left( {{\alpha \over {1 + {\alpha \over 2}}}} \right)P \times {{\left[ {\left( {{{{\alpha \over 2}} \over {1 + {\alpha \over 2}}}} \right)P} \right]}^{{1 \over 2}}}} \over {\left( {{{1 - \alpha } \over {1 + {\alpha \over 2}}}} \right)P}}=(1+2α1−α)P(1+2αα)P×[(1+2α2α)P]21 =(2α2+α)P×[(α2+α)P]12(2(1−α)2+α)P= {{\left( {{{2\alpha } \over {2 + \alpha }}} \right)P \times {{\left[ {\left( {{\alpha \over {2 + \alpha }}} \right)P} \right]}^{{1 \over 2}}}} \over {\left( {{{2(1 - \alpha )} \over {2 + \alpha }}} \right)P}}=(2+α2(1−α))P(2+α2α)P×[(2+αα)P]21 =α1−α×(αP2+α)12= {\alpha \over {1 - \alpha }} \times {\left( {{{\alpha P} \over {2 + \alpha }}} \right)^{{1 \over 2}}}=1−αα×(2+ααP)21 =α32 . P12(1−α)(2+α)12= {{{\alpha ^{{3 \over 2}}}\,.\,{P^{{1 \over 2}}}} \over {(1 - \alpha ){{(2 + \alpha )}^{{1 \over 2}}}}}=(1−α)(2+α)21α23.P21 Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring
