Verified Solution • 2025–26 Session moderate

QJEEM22Ch376d: JEE Main 2022 Chemistry - Class 12 JEEM22Ch376d Solution: In a cell, the following reactions take place F e 2 + → F e 3 + …

In a cell, the following reactions take place

Fe2+→Fe3++e−EFe3+/Fe2+o=0.77V2I−→I2+2e−EI2/I−o=0.54V

The standard electrode potential for the spontaneous reaction in the cell is x ×\times 10 −- 2 V 298 K. The value of x is ____________. (Nearest Integer)

Step-by-Step Verified Solution

Fe+3 Cathode +I− anode ⟶I2+Fe+2\underset{\text { Cathode }}{\mathrm{Fe}^{+3}}+\underset{\text { anode }}{\mathrm{I}^{-}} \longrightarrow \mathrm{I}_2+\mathrm{Fe}^{+2}

Ecell ∘=Ecathode ∘−Eanode ∘E_{\text {cell }}^{\circ}=E_{\text {cathode }}^{\circ}-E_{\text {anode }}^{\circ}

amp;=0.77−0.54amp;=0.23 Vamp;=23×10−2 V\begin{aligned}&=0.77-0.54 \\\\&=0.23 \mathrm{~V} \\\\&=23 \times 10^{-2} \mathrm{~V}\end{aligned}

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