Verified Solution • 2025–26 Session moderate

QJEEM22Ch36a3: JEE Main 2022 Chemistry - Class 12 JEEM22Ch36a3 Solution: The cell potential for the given cell at 298 K Pt

The cell potential for the given cell at 298 K

Pt| H2 (g, 1 bar) | H+ (aq) || Cu2+ (aq) | Cu(s)

is 0.31 V. The pH of the acidic solution is found to be 3, whereas the concentration of Cu2+ is 10 −- x M. The value of x is ___________.

(Given : ECu2+/CuΘE_{C{u^{2 + }}/Cu}^\Theta = 0.34 V and 2.303 RTF{{2.303\,RT} \over F} = 0.06 V)

Step-by-Step Verified Solution

Q=[H+]2[Cu+2]pH2=10−6CpH2=1\mathrm{Q}=\frac{\left[\mathrm{H}^{+}\right]^{2}}{\left[\mathrm{Cu}^{+2}\right] \mathrm{pH}_{2}}=\frac{10^{-6}}{\mathrm{C}} \quad \mathrm{pH}_{2}=1

amp;E=Ecell ∘−0.06nlog⁡Qamp;0.31=0.34−0.062log⁡10−6Camp;log⁡10−6C=1amp;C=10−7Mamp;x=7\begin{aligned}&E=E_{\text {cell }}^{\circ}-\frac{0.06}{n} \log Q \\\\&0.31=0.34-\frac{0.06}{2} \log \frac{10^{-6}}{C} \\\\&\log \frac{10^{-6}}{C}=1 \\\\&C=10^{-7} M \\\\&x=7\end{aligned}

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