QJEEM22Ch352a: JEE Main 2022 Chemistry - Class 11 JEEM22Ch352a Solution: Consider the reaction 4 HNO 3 ( 1 ) + 3 KCl ( s ) → Cl 2 (…

Question

Verified Solution • 2025–26 Session moderate

Consider the reaction

$4 {HNO}_{3} (1) + 3 KCl (s) \to {Cl}_{2} (g) + NOCl (g) + 2 H_{2} O (g) + 3 {KNO}_{3} (s)$

The amount of ${HNO}_{3}$ required to produce $110.0 g$ of ${KNO}_{3}$ is

(Given: Atomic masses of $H, O, N$ and $K$ are $1, 16, 14$ and 39, respectively.)

Accepted Answer

\begin{array}{r} 4 {HNO}_{3} (l) + 3 KCl (s) ⟶ {Cl}_{2} (g) + NOCl (g) + \\ 2 H_{2} O (g) + 3 {KNO}_{3} (s) \end{array}

\because 110 \mathrm{~g}

of

\mathrm{KNO}_{3} \Rightarrow

moles of

\mathrm{KNO}_{3}=\frac{110}{101}

= 1.089 mol

As, 4 mole of

\mathrm{HNO}_{3}

produces

3 \mathrm{~mol}

of

\mathrm{KNO}_{3}

.

Hence, the moles of

\mathrm{HNO}_{3}

required to produce

1.089

moles of

\mathrm{KNO}_{3}=\frac{4}{3} \times 1.089=1.452 \mathrm{~mol}

Hence, mass of

\mathrm{HNO}_{3}

required is

1.452 \times 63

= 91.5 g

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