Verified Solution • 2025–26 Session moderate

QJEEM22Ch3500: JEE Main 2022 Chemistry - Class 12 JEEM22Ch3500 Solution: Match List I with List II. .tg…

Match List I with List II.

List-I
(Anion)		 List-II
(gas evolved on reaction with dil.H 2_2 SO 2_2 )
(A) CO 32−{_3^{2 - }} I. Colourless gas which turns lead acetate paper black.
(B) S 2−^{2 - } II. Colourless gas which turns acidified potassium dichromate solution green.
(C) SO 32−{_3^{2 - }} III. Brown fumes which turns acidified KI solution containing starch blue.
(D) NO 2−{_2^ - } IV. Colourless gas evolved with brisk effervescence, which turns lime water milky.

Choose the correct answer from the options given below :

Multiple Choice Options

  • A A-III, B-I, C-II, D-IV
  • B A-II, B-I, C-IV, D-III
  • C A-IV, B-I, C-III, D-II
  • D A-IV, B-I, C-II, D-III

Step-by-Step Verified Solution

CO32−\mathrm{CO}_{3}^{2-} : On action of dil sulphuric acid, CO2\mathrm{CO}_{2} gas is released which turns lime water milky.

S2−\mathrm{S}^{2-} : On action of dil sulphuric acid, H2 S\mathrm{H}_{2} \mathrm{~S} gas is released which turns lead acetate paper black.

SO32−\mathrm{SO}_{3}^{2-} : On action of dil H2SO4,SO2\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{SO}_{2} gas is evolved which turns acidified potassium dichromate solution green.

NO2−\mathrm{NO}_{2}^{-} : On action of dil H2SO4,NO2\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{NO}_{2} gas is evolved which turns KI\mathrm{KI} solution containg starch blue.

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