QJEEM22Ch33b6: JEE Main 2022 Chemistry - Class 11 JEEM22Ch33b6 Solution: The complete combustion of 0.492 g of an organic compound…

Total organic compound = 0.492 gm

Produced CO₂ = 0.793 gm

$$\therefore$$ Moles of CO₂ = $$\frac{0.793}{44}$$

$$\therefore$$ Moles of C atoms = $$\frac{0.793}{44}$$

$$\therefore$$ Weight of C atoms = $$\frac{0.793}{44}$$ $$\times$$ 12 = 0.216 g

Produced H₂O = 0.442 gm

$$\therefore$$ Moles of H₂O = $$\frac{0.442}{18}$$

$$\therefore$$ Moles of H atoms = $$\frac{0.442}{18}$$

$$\therefore$$ Weight of H atoms = $$\frac{0.442}{18}$$ $$\times$$ 2 = 0.05 g

$$\therefore$$ Weight of O atoms

= 0.492 $$-$$ (0.216 + 0.05)

= 0.226 gm

% by mass of oxygen in compound

= $$\frac{0.226}{0.492}$$ $$\times$$ 100 = 46%