Verified Solution • 2025–26 Session moderate

QJEEM22Ch3193: JEE Main 2022 Chemistry - Class 12 JEEM22Ch3193 Solution: Match List - I with List - II. .tg…

Match List - I with List - II.

List - I List - II
(A) Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l)Cd(s) + 2Ni{(OH)_3}(s) \to CdO(s) + 2Ni{(OH)_2}(s) + {H_2}O(l) (I) Primary battery
(B) Zn(Hg)+HgO(s)→ZnO(s)+Hg(l)Zn(Hg) + HgO(s) \to ZnO(s) + Hg(l) (II) Discharging of secondary battery
(C) 2PbSO4(s)+2H2O(l)→Pb(s)+PbO2(s)+2H2SO4(aq)2PbS{O_4}(s) + 2{H_2}O(l) \to Pb(s) + Pb{O_2}(s) + 2{H_2}S{O_4}(aq) (III) Fuel cell
(D) 2H2(g)+O2(g)→2H2O(l)2{H_2}(g) + {O_2}(g) \to 2{H_2}O(l) (IV) Charging of secondary battery

Choose the correct answer from the options given below:

Multiple Choice Options

  • A (A)−(I),(B)−(II),(C)−(III),(D)−(IV)(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})
  • B (A)−(IV),(B)−(I),(C)−(II),(D)−(III)(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{III})
  • C (A)−(II),(B)−(I),(C)−(IV),(D)−(III)(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{III})
  • D (A)−(II),(B)−(I),(C)−(III),(D)−(IV)(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})

Step-by-Step Verified Solution

(a) Cd(s)+2Ni(OH)3( s)→CdO(s)+2Ni(OH)2( s)\mathrm{Cd}(\mathrm{s})+2 \mathrm{Ni}(\mathrm{OH})_3(\mathrm{~s}) \rightarrow \mathrm{CdO}(\mathrm{s})+2 \mathrm{Ni}(\mathrm{OH})_2(\mathrm{~s}) +H2O(l)+\mathrm{H}_2 \mathrm{O}(l) Discharge of secondary Battery

(b) Zn(Hg)+HgO\mathrm{Zn}(\mathrm{Hg})+\mathrm{HgO} (s) →ZnO(s)+Hg(l)\rightarrow \mathrm{ZnO}(\mathrm{s})+\mathrm{Hg}(l) (Primary Battery Mercury cell)

(c) 2PbSO4( s)+2H2O(l)→Pb(s)+PbO2( s)+2 \mathrm{PbSO}_4(\mathrm{~s})+2 \mathrm{H}_2 \mathrm{O}(l) \rightarrow \mathrm{Pb}(\mathrm{s})+\mathrm{PbO}_2(\mathrm{~s})+ 2H2SO4(aq)2 \mathrm{H}_2 \mathrm{SO}_4(\mathrm{aq}) (Charging of secondary Battery)

(d) 2H2( g)+O2( g)→2H2O(l)2 \mathrm{H}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{H}_2 \mathrm{O}(l) (Fuel cell)

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