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QJEEM22Ch2bbc: JEE Main 2022 Chemistry - Class 11 JEEM22Ch2bbc Solution: In the given reaction, if one mole of each of and with of gives …

In the given reaction,

X+Y+3Z⇆XYZ3X+Y+3 Z \leftrightarrows X YZ_{3}

if one mole of each of XX and YY with 0.05 mol0.05 \mathrm{~mol} of ZZ gives compound XYZ3X Y Z_{3} . (Given : Atomic masses of X,YX, Y and ZZ are 10, 20 and 30 amu, respectively.) The yield of XYZ3X YZ_{3} is _____________ g. (Nearest integer)

Step-by-Step Verified Solution

Xnmoles =1+Y1+3Z0.05⇌XYZ3\underset{n_{\text {moles }}=1}{X}+\underset{1}{Y}+\underset{0.05}{3 Z} \rightleftharpoons X Y Z_{3}

Limiting reagent is Z=0.053=.016Z=\frac{0.05}{3}=.016

3 moles of Z→1Z \rightarrow 1 mole of XYZ3X Y Z_{3}

0.050.05 mole of Z→13×0.05Z \rightarrow \frac{1}{3} \times 0.05 mole of XYZ3X Y Z_{3}

M.wt. of XYZ3=10+20+90\mathrm{XYZ}_{3}=10+20+90

=120 amu=120\, \mathrm{amu}

Wt. of XYZ3=.053×120X Y Z_{3}=\frac{.05}{3} \times 120

=2 g=2 \mathrm{~g}

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