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QJEEM22Ch2b2a: JEE Main 2022 Chemistry - Class 12 JEEM22Ch2b2a Solution: If the initial pressure of a gas is 0.03 atm, the mass of the…

JEE Main 2022 (Online) 27th June Evening Shift Chemistry - Surface Chemistry Question 41 English

If the initial pressure of a gas is 0.03 atm, the mass of the gas adsorbed per gram of the adsorbent is ___________ ×\times 10 −- 2 g.

Step-by-Step Verified Solution

Given that log⁡K=\log \mathrm{K}= intercept =0.602=log⁡4=0.602=\log 4

∴K=4\therefore \mathrm{K}=4

Slope =1n=1=\frac{1}{\mathrm{n}}=1

and initial pressure =0.03 atm=0.03 \mathrm{~atm}

xm=K(p)1/n=4×0.03=0.12=12×10−2\frac{x}{m}=K(p)^{1 / n}=4 \times 0.03=0.12=12 \times 10^{-2}

mass of gas absorbed per gm of adsorbent

=12×10−2 g=12 \times 10^{-2} \mathrm{~g}

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