Verified Solution • 2025–26 Session moderate

QJEEM22Ch23df: JEE Main 2022 Chemistry - Class 12 JEEM22Ch23df Solution: The disproportionation of in acidic medium resulted in the…

The disproportionation of MnO42−\mathrm{MnO}_{4}^{2-} in acidic medium resulted in the formation of two manganese compounds A\mathrm{A} and B\mathrm{B} . If the oxidation state of Mn\mathrm{Mn} in B\mathrm{B} is smaller than that of A, then the spin-only magnetic moment (μ)(\mu) value of B in BM is __________. (Nearest integer)

Step-by-Step Verified Solution

3MnO4−2+6+4H+→MnO2+4+MnO4−+73 \overset{+6}{\mathrm{MnO}_{4}^{-2}}+4 \mathrm{H}^{+} \rightarrow \overset{+4}{\mathrm{MnO}_{2}}+\overset{+7}{\mathrm{MnO}_{4}^{-}}

Mn→4s23d5\mathrm{Mn} \rightarrow 4 s^{2} 3 d^{5}

Mn+4→3d3\mathrm{Mn}^{+4} \rightarrow 3 d^{3}

n=3\mathrm{n}=3

μamp;=n(n+2)amp;=3(5)amp;=15amp;=3.87≈4 B.M. \begin{aligned}\mu &=\sqrt{n(n+2)} \\\\&=\sqrt{3(5)} \\\\&=\sqrt{15} \\\\&=3.87 \approx 4 \text { B.M. }\end{aligned}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring